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If the vapor pressure of pure solvent A is 100 mmHg, and the mole fraction of A

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Question: If the vapor pressure of pure solvent A is 100 mmHg, and the mole fraction of A in the solution is 0.5, what is the vapor pressure of the solution according to Raoult\'s Law?

Options:

  1. 50 mmHg
  2. 100 mmHg
  3. 150 mmHg
  4. 200 mmHg

Correct Answer: 50 mmHg

Solution:

According to Raoult\'s Law, P_solution = X_A * P_A^0 = 0.5 * 100 mmHg = 50 mmHg.

If the vapor pressure of pure solvent A is 100 mmHg, and the mole fraction of A

Practice Questions

Q1
If the vapor pressure of pure solvent A is 100 mmHg, and the mole fraction of A in the solution is 0.5, what is the vapor pressure of the solution according to Raoult's Law?
  1. 50 mmHg
  2. 100 mmHg
  3. 150 mmHg
  4. 200 mmHg

Questions & Step-by-Step Solutions

If the vapor pressure of pure solvent A is 100 mmHg, and the mole fraction of A in the solution is 0.5, what is the vapor pressure of the solution according to Raoult's Law?
  • Step 1: Identify the vapor pressure of pure solvent A, which is given as 100 mmHg.
  • Step 2: Identify the mole fraction of solvent A in the solution, which is given as 0.5.
  • Step 3: Recall Raoult's Law, which states that the vapor pressure of the solution (P_solution) is equal to the mole fraction of the solvent (X_A) multiplied by the vapor pressure of the pure solvent (P_A^0).
  • Step 4: Substitute the values into the formula: P_solution = X_A * P_A^0.
  • Step 5: Calculate P_solution by multiplying 0.5 (mole fraction) by 100 mmHg (vapor pressure of pure solvent): 0.5 * 100 mmHg = 50 mmHg.
  • Step 6: Conclude that the vapor pressure of the solution is 50 mmHg.
  • Raoult's Law – Raoult's Law states that the vapor pressure of a solvent in a solution is equal to the vapor pressure of the pure solvent multiplied by the mole fraction of the solvent in the solution.
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