If 15 grams of sugar is dissolved in 250 mL of solution, what is the molarity of the solution? (Molar mass of sugar = 180 g/mol)

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Q: If 15 grams of sugar is dissolved in 250 mL of solution, what is the molarity of the solution? (Molar mass of sugar = 180 g/mol)

Solution: Moles of sugar = 15 g / 180 g/mol = 0.0833 moles. Molarity = 0.0833 moles / 0.25 L = 0.333 M.

Steps: 8

Step 1: Identify the amount of sugar in grams, which is 15 grams.
Step 2: Identify the molar mass of sugar, which is 180 g/mol.
Step 3: Calculate the number of moles of sugar using the formula: Moles = Mass (g) / Molar Mass (g/mol). So, Moles of sugar = 15 g / 180 g/mol.
Step 4: Perform the calculation: 15 divided by 180 equals 0.0833 moles.
Step 5: Convert the volume of the solution from mL to L. Since 250 mL is equal to 0.25 L.
Step 6: Use the formula for molarity: Molarity (M) = Moles of solute / Volume of solution (L).
Step 7: Substitute the values: Molarity = 0.0833 moles / 0.25 L.
Step 8: Perform the calculation: 0.0833 divided by 0.25 equals 0.333 M.