What is the pH of a buffer solution made from 0.2 M acetic acid and 0.2 M sodium

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Question: What is the pH of a buffer solution made from 0.2 M acetic acid and 0.2 M sodium acetate?

Options:

Correct Answer: 4.76

Solution:

Using the Henderson-Hasselbalch equation, pH = pKa + log([A-]/[HA]) = 4.76.

What is the pH of a buffer solution made from 0.2 M acetic acid and 0.2 M sodium acetate?

What is the pH of a buffer solution made from 0.2 M acetic acid and 0.2 M sodium acetate?

Step 1: Identify the components of the buffer solution. We have acetic acid (HA) and sodium acetate (A-).
Step 2: Determine the concentration of acetic acid (HA), which is 0.2 M.
Step 3: Determine the concentration of sodium acetate (A-), which is also 0.2 M.
Step 4: Find the pKa of acetic acid. The pKa is approximately 4.76.
Step 5: Use the Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]).
Step 6: Substitute the values into the equation: pH = 4.76 + log(0.2/0.2).
Step 7: Calculate the log(0.2/0.2), which is log(1) = 0.
Step 8: Therefore, pH = 4.76 + 0 = 4.76.

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