In a closed system, if the volume is decreased, what will happen to the equilibr

In a closed system, if the volume is decreased, what will happen to the equilibrium of the reaction 2A(g) + B(g) ⇌ 3C(g)?

In a closed system, if the volume is decreased, what will happen to the equilibrium of the reaction 2A(g) + B(g) ⇌ 3C(g)?

Step 1: Understand that the reaction involves gases: 2A(g) + B(g) ⇌ 3C(g).
Step 2: Count the number of gas molecules on each side of the reaction.
Step 3: On the left side (reactants), there are 2 moles of A and 1 mole of B, totaling 3 moles of gas.
Step 4: On the right side (products), there are 3 moles of C, totaling 3 moles of gas.
Step 5: Recognize that decreasing the volume of the system increases the pressure.
Step 6: According to Le Chatelier's principle, the equilibrium will shift to reduce the pressure.
Step 7: Since both sides have the same number of moles of gas (3 moles), the equilibrium will not shift to either side.

No concepts available.