What is the limiting reagent when 3 moles of A react with 2 moles of B to produc

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Question: What is the limiting reagent when 3 moles of A react with 2 moles of B to produce 4 moles of C?

Options:

Correct Answer: B

Solution:

The reaction requires 1.5 moles of B for 3 moles of A. Since only 2 moles of B are available, B is the limiting reagent.

What is the limiting reagent when 3 moles of A react with 2 moles of B to produce 4 moles of C?

What is the limiting reagent when 3 moles of A react with 2 moles of B to produce 4 moles of C?

Step 1: Identify the reactants and products. Here, A and B are the reactants, and C is the product.
Step 2: Write down the amount of each reactant available. We have 3 moles of A and 2 moles of B.
Step 3: Determine the stoichiometric ratio from the reaction. For every 1 mole of A, we need 1.5 moles of B to produce C.
Step 4: Calculate how much B is needed for the available A. Since we have 3 moles of A, we need 3 moles of A * 1.5 moles of B/mole of A = 4.5 moles of B.
Step 5: Compare the required amount of B (4.5 moles) with the available amount of B (2 moles).
Step 6: Since we need 4.5 moles of B but only have 2 moles, B is the limiting reagent.

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