What is the limiting reagent when 3 moles of A react with 2 moles of B to produce 4 moles of C?
Practice Questions
1 question
Q1
What is the limiting reagent when 3 moles of A react with 2 moles of B to produce 4 moles of C?
A
B
C
None
The reaction requires 1.5 moles of B for 3 moles of A. Since only 2 moles of B are available, B is the limiting reagent.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the limiting reagent when 3 moles of A react with 2 moles of B to produce 4 moles of C?
Solution: The reaction requires 1.5 moles of B for 3 moles of A. Since only 2 moles of B are available, B is the limiting reagent.
Steps: 6
Step 1: Identify the reactants and products. Here, A and B are the reactants, and C is the product.
Step 2: Write down the amount of each reactant available. We have 3 moles of A and 2 moles of B.
Step 3: Determine the stoichiometric ratio from the reaction. For every 1 mole of A, we need 1.5 moles of B to produce C.
Step 4: Calculate how much B is needed for the available A. Since we have 3 moles of A, we need 3 moles of A * 1.5 moles of B/mole of A = 4.5 moles of B.
Step 5: Compare the required amount of B (4.5 moles) with the available amount of B (2 moles).
Step 6: Since we need 4.5 moles of B but only have 2 moles, B is the limiting reagent.
