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If 5 g of CaCO3 decomposes completely, how many grams of CaO are produced?
If 5 g of CaCO3 decomposes completely, how many grams of CaO are produced?
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Q1
If 5 g of CaCO3 decomposes completely, how many grams of CaO are produced?
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CaCO3 → CaO + CO2. Molar mass of CaCO3 = 100 g, CaO = 56 g. 5 g of CaCO3 produces (5 g * 56 g) / 100 g = 2.8 g of CaO.
Questions & Step-by-step Solutions
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Q: If 5 g of CaCO3 decomposes completely, how many grams of CaO are produced?
Solution:
CaCO3 → CaO + CO2. Molar mass of CaCO3 = 100 g, CaO = 56 g. 5 g of CaCO3 produces (5 g * 56 g) / 100 g = 2.8 g of CaO.
Steps: 6
Show Steps
Step 1: Write down the decomposition reaction of calcium carbonate (CaCO3): CaCO3 → CaO + CO2.
Step 2: Calculate the molar mass of CaCO3. It is 40 (Ca) + 12 (C) + 3*16 (O) = 100 g/mol.
Step 3: Calculate the molar mass of calcium oxide (CaO). It is 40 (Ca) + 16 (O) = 56 g/mol.
Step 4: Use the mass of CaCO3 given in the problem, which is 5 g.
Step 5: Set up the proportion to find out how many grams of CaO are produced from 5 g of CaCO3: (5 g of CaCO3) * (56 g of CaO / 100 g of CaCO3).
Step 6: Calculate the result: (5 * 56) / 100 = 2.8 g of CaO.
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