If 5 g of CaCO3 decomposes completely, how many grams of CaO are produced?

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Question: If 5 g of CaCO3 decomposes completely, how many grams of CaO are produced?

Options:

Correct Answer: 4 g

Solution:

CaCO3 → CaO + CO2. Molar mass of CaCO3 = 100 g, CaO = 56 g. 5 g of CaCO3 produces (5 g * 56 g) / 100 g = 2.8 g of CaO.

If 5 g of CaCO3 decomposes completely, how many grams of CaO are produced?

If 5 g of CaCO3 decomposes completely, how many grams of CaO are produced?

Step 1: Write down the decomposition reaction of calcium carbonate (CaCO3): CaCO3 → CaO + CO2.
Step 2: Calculate the molar mass of CaCO3. It is 40 (Ca) + 12 (C) + 3*16 (O) = 100 g/mol.
Step 3: Calculate the molar mass of calcium oxide (CaO). It is 40 (Ca) + 16 (O) = 56 g/mol.
Step 4: Use the mass of CaCO3 given in the problem, which is 5 g.
Step 5: Set up the proportion to find out how many grams of CaO are produced from 5 g of CaCO3: (5 g of CaCO3) * (56 g of CaO / 100 g of CaCO3).
Step 6: Calculate the result: (5 * 56) / 100 = 2.8 g of CaO.

Stoichiometry – The calculation of reactants and products in chemical reactions based on balanced equations.
Molar Mass Calculation – Understanding how to calculate the molar mass of compounds to convert between grams and moles.
Decomposition Reactions – Recognizing the type of reaction where a single compound breaks down into two or more products.