What is the hybridization of the central atom in [Ni(CN)4]2-?

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Question: What is the hybridization of the central atom in [Ni(CN)4]2-?

Options:

Correct Answer: dsp2

Solution:

In [Ni(CN)4]2-, nickel is in the +2 oxidation state and undergoes dsp2 hybridization to accommodate the four cyanide ligands.

What is the hybridization of the central atom in [Ni(CN)4]2-?

What is the hybridization of the central atom in [Ni(CN)4]2-?

Step 1: Identify the central atom in the complex [Ni(CN)4]2-. The central atom is nickel (Ni).
Step 2: Determine the oxidation state of nickel in the complex. Since the overall charge is -2 and each cyanide (CN) ligand has a charge of -1, nickel must be in the +2 oxidation state.
Step 3: Count the number of ligands attached to the central atom. There are four cyanide ligands (CN) attached to nickel.
Step 4: Determine the type of hybridization needed for nickel to bond with the four ligands. Since there are four ligands, we need to use dsp2 hybridization.
Step 5: Conclude that the hybridization of the central atom nickel in [Ni(CN)4]2- is dsp2.

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