What is the oxidation state of chromium in K2[Cr2O7]?
Practice Questions
1 question
Q1
What is the oxidation state of chromium in K2[Cr2O7]?
+2
+3
+6
+7
In K2[Cr2O7], the overall charge is 0. Each potassium (K) has a +1 charge, and each oxygen (O) has a -2 charge. Solving for chromium gives an oxidation state of +6.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the oxidation state of chromium in K2[Cr2O7]?
Solution: In K2[Cr2O7], the overall charge is 0. Each potassium (K) has a +1 charge, and each oxygen (O) has a -2 charge. Solving for chromium gives an oxidation state of +6.
Steps: 9
Step 1: Identify the formula K2[Cr2O7]. This means there are 2 potassium (K) ions and 2 chromium (Cr) ions in the compound.
Step 2: Determine the charge of potassium (K). Each potassium ion has a charge of +1.
Step 3: Calculate the total charge from potassium. Since there are 2 potassium ions, the total charge from K is 2 * (+1) = +2.
Step 4: Determine the charge of oxygen (O). Each oxygen ion has a charge of -2.
Step 5: Calculate the total charge from oxygen. There are 7 oxygen ions, so the total charge from O is 7 * (-2) = -14.
Step 6: Write the equation for the overall charge. The overall charge of the compound is 0, so we can set up the equation: +2 (from K) + charge from Cr + (-14 from O) = 0.
Step 7: Simplify the equation. This gives us: charge from Cr - 12 = 0.
Step 8: Solve for the charge from Cr. This means charge from Cr = +12.
Step 9: Since there are 2 chromium ions, divide the total charge from Cr by 2 to find the oxidation state of one chromium ion: +12 / 2 = +6.
