A 2 kg object is thrown upwards with a speed of 10 m/s. What is the maximum heig

A 2 kg object is thrown upwards with a speed of 10 m/s. What is the maximum height it reaches?

A 2 kg object is thrown upwards with a speed of 10 m/s. What is the maximum height it reaches?

Step 1: Identify the mass of the object, which is 2 kg.
Step 2: Identify the initial speed of the object, which is 10 m/s.
Step 3: Use the formula for kinetic energy (KE) to find the initial kinetic energy: KE_initial = 0.5 × mass × (speed)².
Step 4: Plug in the values: KE_initial = 0.5 × 2 kg × (10 m/s)² = 0.5 × 2 × 100 = 100 Joules.
Step 5: Use the formula for potential energy (PE) at maximum height: PE_max = mass × gravity × height.
Step 6: The gravitational acceleration (gravity) is approximately 9.8 m/s².
Step 7: Set the initial kinetic energy equal to the potential energy at maximum height: 100 Joules = 2 kg × 9.8 m/s² × h.
Step 8: Rearrange the equation to solve for height (h): h = 100 Joules / (2 kg × 9.8 m/s²).
Step 9: Calculate the height: h = 100 / 19.6 ≈ 5.1 meters.

Kinetic Energy and Potential Energy – The question tests the understanding of the conversion between kinetic energy (KE) and potential energy (PE) in the context of an object thrown vertically.
Energy Conservation Principle – It assesses the application of the principle of conservation of mechanical energy, where the initial kinetic energy is converted to potential energy at the maximum height.
Gravitational Acceleration – The problem involves the use of gravitational acceleration (9.8 m/s²) in calculating the potential energy at maximum height.