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A force of 15 N is applied at an angle of 60 degrees to a lever arm of 1 m. What
A force of 15 N is applied at an angle of 60 degrees to a lever arm of 1 m. What is the torque?
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Practice Questions
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Q1
A force of 15 N is applied at an angle of 60 degrees to a lever arm of 1 m. What is the torque?
7.5 Nm
12.5 Nm
15 Nm
25 Nm
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Torque = Force × Distance × sin(θ) = 15 N × 1 m × sin(60°) = 15 N × 1 m × (√3/2) = 12.5 Nm.
Questions & Step-by-step Solutions
1 item
Q
Q: A force of 15 N is applied at an angle of 60 degrees to a lever arm of 1 m. What is the torque?
Solution:
Torque = Force × Distance × sin(θ) = 15 N × 1 m × sin(60°) = 15 N × 1 m × (√3/2) = 12.5 Nm.
Steps: 9
Show Steps
Step 1: Identify the force applied, which is 15 N.
Step 2: Identify the distance from the pivot point to where the force is applied, which is 1 m.
Step 3: Identify the angle at which the force is applied, which is 60 degrees.
Step 4: Use the formula for torque: Torque = Force × Distance × sin(θ).
Step 5: Substitute the values into the formula: Torque = 15 N × 1 m × sin(60°).
Step 6: Calculate sin(60°), which is √3/2.
Step 7: Substitute sin(60°) into the formula: Torque = 15 N × 1 m × (√3/2).
Step 8: Calculate the torque: Torque = 15 N × 1 m × 0.866 (approximately √3/2).
Step 9: Multiply the values: Torque = 15 N × 1 m × 0.866 = 12.99 Nm (approximately 12.5 Nm).
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