A cylinder rolls down an incline of angle θ. What is the acceleration of the center of mass of the cylinder?

Practice Questions

1 question
Q1
A cylinder rolls down an incline of angle θ. What is the acceleration of the center of mass of the cylinder?
  1. g sin(θ)
  2. g sin(θ)/2
  3. g sin(θ)/3
  4. g sin(θ)/4

Questions & Step-by-step Solutions

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Q
Q: A cylinder rolls down an incline of angle θ. What is the acceleration of the center of mass of the cylinder?
Solution: The acceleration a = g sin(θ) / (1 + k^2/r^2) where k^2/r^2 for a solid cylinder is 1/2. Thus, a = g sin(θ) / (1 + 1/2) = g sin(θ)/2.
Steps: 0

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