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A 1 kg mass is dropped from a height of 1 m. What is the speed just before it hi
A 1 kg mass is dropped from a height of 1 m. What is the speed just before it hits the ground?
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Practice Questions
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A 1 kg mass is dropped from a height of 1 m. What is the speed just before it hits the ground?
1 m/s
2 m/s
3 m/s
4 m/s
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Using conservation of energy, v = sqrt(2gh) = sqrt(2 * 9.8 * 1) = 4.43 m/s.
Questions & Step-by-step Solutions
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Q
Q: A 1 kg mass is dropped from a height of 1 m. What is the speed just before it hits the ground?
Solution:
Using conservation of energy, v = sqrt(2gh) = sqrt(2 * 9.8 * 1) = 4.43 m/s.
Steps: 6
Show Steps
Step 1: Understand that when the mass is dropped, it has potential energy due to its height.
Step 2: Recognize that as it falls, this potential energy converts into kinetic energy.
Step 3: Use the formula for speed just before hitting the ground, which is derived from energy conservation: v = sqrt(2gh).
Step 4: Identify the values: g (acceleration due to gravity) is approximately 9.8 m/s², and h (height) is 1 m.
Step 5: Plug the values into the formula: v = sqrt(2 * 9.8 * 1).
Step 6: Calculate the value: 2 * 9.8 = 19.6, then take the square root of 19.6, which is approximately 4.43 m/s.
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