Question: A 2 kg ball is thrown vertically upwards with a speed of 15 m/s. What is the maximum height it reaches?
Options:
Correct Answer: 10 m
Solution:
Using conservation of energy, KE at the bottom = PE at the top. 0.5mv^2 = mgh. Solving gives h = v^2/(2g) = (15^2)/(2*9.8) = 11.47 m.