A force of 15 N is applied at an angle of 30° to the horizontal while moving an object 4 m. What is the work done by the force?

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Q: A force of 15 N is applied at an angle of 30° to the horizontal while moving an object 4 m. What is the work done by the force?

Solution: Work done = F × d × cos(θ) = 15 N × 4 m × cos(30°) = 15 N × 4 m × (√3/2) = 60 J.

Steps: 10

Step 1: Identify the force applied, which is 15 N.
Step 2: Identify the distance moved by the object, which is 4 m.
Step 3: Identify the angle of the force with respect to the horizontal, which is 30°.
Step 4: Use the formula for work done: Work = Force × Distance × cos(Angle).
Step 5: Substitute the values into the formula: Work = 15 N × 4 m × cos(30°).
Step 6: Calculate cos(30°), which is √3/2.
Step 7: Substitute cos(30°) into the formula: Work = 15 N × 4 m × (√3/2).
Step 8: Calculate the multiplication: 15 N × 4 m = 60 N·m.
Step 9: Now multiply 60 N·m by (√3/2) to find the work done.
Step 10: The final answer for work done is approximately 60 J.