A flywheel is rotating with an angular velocity of 10 rad/s. If it is subjected

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Question: A flywheel is rotating with an angular velocity of 10 rad/s. If it is subjected to a torque of 5 Nm, what is the angular acceleration?

Options:

Correct Answer: 2 rad/s²

Solution:

Using τ = Iα, where τ is torque, I is moment of inertia, and α is angular acceleration. Assuming I = 25 kg·m², α = τ/I = 5/25 = 0.2 rad/s².

A flywheel is rotating with an angular velocity of 10 rad/s. If it is subjected to a torque of 5 Nm, what is the angular acceleration?

A flywheel is rotating with an angular velocity of 10 rad/s. If it is subjected to a torque of 5 Nm, what is the angular acceleration?

Step 1: Identify the given values. We have a torque (τ) of 5 Nm and a moment of inertia (I) of 25 kg·m².
Step 2: Write down the formula that relates torque, moment of inertia, and angular acceleration. The formula is τ = Iα.
Step 3: Rearrange the formula to solve for angular acceleration (α). This gives us α = τ / I.
Step 4: Substitute the known values into the rearranged formula. We have α = 5 Nm / 25 kg·m².
Step 5: Perform the calculation. Divide 5 by 25 to get α = 0.2 rad/s².
Step 6: State the final answer. The angular acceleration is 0.2 rad/s².

Torque and Angular Acceleration – This question tests the understanding of the relationship between torque, moment of inertia, and angular acceleration using the formula τ = Iα.
Moment of Inertia – The problem assumes a specific moment of inertia (I = 25 kg·m²), which is crucial for calculating angular acceleration.