If a liquid has a surface tension of 0.05 N/m, what is the work done in increasi

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Question: If a liquid has a surface tension of 0.05 N/m, what is the work done in increasing the surface area by 1 m²?

Options:

Correct Answer: 0.05 J

Solution:

Work done = Surface Tension × Change in Area = 0.05 N/m × 1 m² = 0.05 J.

If a liquid has a surface tension of 0.05 N/m, what is the work done in increasing the surface area by 1 m²?

If a liquid has a surface tension of 0.05 N/m, what is the work done in increasing the surface area by 1 m²?

Step 1: Understand that surface tension is a force that acts at the surface of a liquid.
Step 2: Know that the unit of surface tension is Newtons per meter (N/m).
Step 3: Recognize that work done in increasing the surface area can be calculated using the formula: Work done = Surface Tension × Change in Area.
Step 4: Identify the given values: Surface Tension = 0.05 N/m and Change in Area = 1 m².
Step 5: Substitute the values into the formula: Work done = 0.05 N/m × 1 m².
Step 6: Calculate the result: Work done = 0.05 J.

Surface Tension – Surface tension is the energy required to increase the surface area of a liquid due to cohesive forces between liquid molecules.
Work Done – Work done in this context is calculated as the product of surface tension and the change in surface area.