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If a liquid has a surface tension of 0.05 N/m, what is the work done in increasi
If a liquid has a surface tension of 0.05 N/m, what is the work done in increasing the surface area by 1 m²?
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Practice Questions
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Q1
If a liquid has a surface tension of 0.05 N/m, what is the work done in increasing the surface area by 1 m²?
0.05 J
0.1 J
0.2 J
0.5 J
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Work done = Surface Tension × Change in Area = 0.05 N/m × 1 m² = 0.05 J.
Questions & Step-by-step Solutions
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Q
Q: If a liquid has a surface tension of 0.05 N/m, what is the work done in increasing the surface area by 1 m²?
Solution:
Work done = Surface Tension × Change in Area = 0.05 N/m × 1 m² = 0.05 J.
Steps: 6
Show Steps
Step 1: Understand that surface tension is a force that acts at the surface of a liquid.
Step 2: Know that the unit of surface tension is Newtons per meter (N/m).
Step 3: Recognize that work done in increasing the surface area can be calculated using the formula: Work done = Surface Tension × Change in Area.
Step 4: Identify the given values: Surface Tension = 0.05 N/m and Change in Area = 1 m².
Step 5: Substitute the values into the formula: Work done = 0.05 N/m × 1 m².
Step 6: Calculate the result: Work done = 0.05 J.
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