A force of 20 N is applied at an angle of 60 degrees to a lever arm of length 0.

Practice Questions

Q1
A force of 20 N is applied at an angle of 60 degrees to a lever arm of length 0.5 m. What is the torque about the pivot?
  1. 5 Nm
  2. 10 Nm
  3. 8.66 Nm
  4. 17.32 Nm

Questions & Step-by-Step Solutions

A force of 20 N is applied at an angle of 60 degrees to a lever arm of length 0.5 m. What is the torque about the pivot?
  • Step 1: Identify the force applied, which is 20 N.
  • Step 2: Identify the length of the lever arm, which is 0.5 m.
  • Step 3: Identify the angle at which the force is applied, which is 60 degrees.
  • Step 4: Use the formula for torque: Torque (τ) = Force (F) × Length of lever arm (r) × sin(angle).
  • Step 5: Substitute the values into the formula: τ = 20 N × 0.5 m × sin(60°).
  • Step 6: Calculate sin(60°), which is √3/2 or approximately 0.866.
  • Step 7: Substitute sin(60°) into the equation: τ = 20 N × 0.5 m × (√3/2).
  • Step 8: Calculate the torque: τ = 20 N × 0.5 m × 0.866 = 8.66 Nm.
  • Torque Calculation – Understanding how to calculate torque using the formula τ = F × r × sin(θ), where F is the force, r is the distance from the pivot, and θ is the angle between the force and the lever arm.
  • Trigonometric Functions – Applying the sine function to find the effective component of the force that contributes to torque.
  • Units of Measurement – Recognizing that torque is measured in Newton-meters (Nm) and ensuring unit consistency in calculations.
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