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A force of 20 N is applied at an angle of 60 degrees to a lever arm of length 0.5 m. What is the torque about the pivot?

Practice Questions

1 question
Q1
A force of 20 N is applied at an angle of 60 degrees to a lever arm of length 0.5 m. What is the torque about the pivot?
  1. 5 Nm
  2. 10 Nm
  3. 8.66 Nm
  4. 17.32 Nm

Questions & Step-by-step Solutions

1 item
Q
Q: A force of 20 N is applied at an angle of 60 degrees to a lever arm of length 0.5 m. What is the torque about the pivot?
Solution: Torque (τ) = F × r × sin(θ) = 20 N × 0.5 m × sin(60°) = 20 N × 0.5 m × (√3/2) = 8.66 Nm.
Steps: 0

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