A mass-spring system is subjected to a periodic force. If the amplitude of oscil

Practice Questions

A mass-spring system is subjected to a periodic force. If the amplitude of oscillation is 0.1 m and the frequency is 2 Hz, what is the maximum velocity of the mass?

0.4 m/s
0.2 m/s
0.1 m/s
0.8 m/s

Questions & Step-by-Step Solutions

A mass-spring system is subjected to a periodic force. If the amplitude of oscillation is 0.1 m and the frequency is 2 Hz, what is the maximum velocity of the mass?

Step 1: Identify the given values. The amplitude (A) is 0.1 m and the frequency (f) is 2 Hz.
Step 2: Calculate the angular frequency (ω) using the formula ω = 2πf. Substitute f = 2 Hz into the formula.
Step 3: Calculate ω: ω = 2π * 2 = 4π radians per second.
Step 4: Use the formula for maximum velocity (v_max), which is v_max = Aω.
Step 5: Substitute the values of A and ω into the formula: v_max = 0.1 * (4π).
Step 6: Calculate v_max: v_max = 0.1 * 4π ≈ 0.4 m/s.

Simple Harmonic Motion – The behavior of a mass-spring system under periodic forces, characterized by parameters such as amplitude and frequency.
Maximum Velocity in Oscillations – The maximum speed of an oscillating mass, calculated using the formula v_max = Aω, where A is amplitude and ω is angular frequency.
Angular Frequency – The rate of oscillation in radians per second, calculated as ω = 2πf, where f is the frequency in hertz.

A mass-spring system is subjected to a periodic force. If the amplitude of oscil

Practice Questions

Questions & Step-by-Step Solutions

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