Two particles A and B of masses m1 and m2 are moving in a circular path with angular velocities ω1 and ω2 respectively. What is the total angular momentum of the system?
Practice Questions
1 question
Q1
Two particles A and B of masses m1 and m2 are moving in a circular path with angular velocities ω1 and ω2 respectively. What is the total angular momentum of the system?
m1ω1 + m2ω2
m1ω1 - m2ω2
m1ω1m2ω2
m1ω1 + m2ω2/2
Total angular momentum L = m1ω1 + m2ω2 for particles moving in the same direction.
Questions & Step-by-step Solutions
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Q
Q: Two particles A and B of masses m1 and m2 are moving in a circular path with angular velocities ω1 and ω2 respectively. What is the total angular momentum of the system?
Solution: Total angular momentum L = m1ω1 + m2ω2 for particles moving in the same direction.
Steps: 7
Step 1: Understand that angular momentum is a measure of how much motion an object has while rotating.
Step 2: Identify the two particles A and B with their respective masses m1 and m2.
Step 3: Note the angular velocities of the particles, which are ω1 for particle A and ω2 for particle B.
Step 4: Recognize that if both particles are moving in the same direction, their angular momenta can be added together.
Step 5: Calculate the angular momentum of particle A using the formula: L1 = m1 * ω1.
Step 6: Calculate the angular momentum of particle B using the formula: L2 = m2 * ω2.
Step 7: Add the angular momenta of both particles to find the total angular momentum: L = L1 + L2 = m1 * ω1 + m2 * ω2.
