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What is the path difference for light waves from two coherent sources at an angl

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Question: What is the path difference for light waves from two coherent sources at an angle of 45° to the line joining the sources at a distance of 1 m?

Options:

  1. 0.5 m
  2. 0.707 m
  3. 1 m
  4. 0.25 m

Correct Answer: 0.707 m

Solution: 

Path difference = d sin θ = 1 m * sin(45°) = 1 m * √2/2 = 0.707 m.

What is the path difference for light waves from two coherent sources at an angl

Practice Questions

Q1
What is the path difference for light waves from two coherent sources at an angle of 45° to the line joining the sources at a distance of 1 m?
  1. 0.5 m
  2. 0.707 m
  3. 1 m
  4. 0.25 m

Questions & Step-by-Step Solutions

What is the path difference for light waves from two coherent sources at an angle of 45° to the line joining the sources at a distance of 1 m?
  • Step 1: Identify the formula for path difference, which is given by the equation: Path difference = d * sin(θ).
  • Step 2: Determine the values needed for the formula. Here, d (the distance between the sources) is 1 m and θ (the angle) is 45°.
  • Step 3: Substitute the values into the formula: Path difference = 1 m * sin(45°).
  • Step 4: Calculate sin(45°). The value of sin(45°) is √2/2.
  • Step 5: Multiply the distance by the sine value: Path difference = 1 m * (√2/2).
  • Step 6: Simplify the calculation: Path difference = 0.707 m.
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