In a thin film of oil on water, if the thickness of the film is 500 nm, what is
Practice Questions
Q1
In a thin film of oil on water, if the thickness of the film is 500 nm, what is the condition for destructive interference for light of wavelength 600 nm?
2t = (m + 1/2)λ
2t = mλ
t = (m + 1/2)λ
t = mλ
Questions & Step-by-Step Solutions
In a thin film of oil on water, if the thickness of the film is 500 nm, what is the condition for destructive interference for light of wavelength 600 nm?
Step 1: Understand that we are dealing with a thin film of oil on water.
Step 2: Know that the thickness of the oil film is given as 500 nm.
Step 3: Recognize that the wavelength of light we are considering is 600 nm.
Step 4: Recall the formula for destructive interference in a thin film: 2t = (m + 1/2)λ.
Step 5: Identify 't' as the thickness of the film, which is 500 nm.
Step 6: Substitute the values into the formula: 2(500 nm) = (m + 1/2)(600 nm).
Step 7: Simplify the left side: 1000 nm = (m + 1/2)(600 nm).
Step 8: Divide both sides by 600 nm to isolate (m + 1/2): (1000 nm / 600 nm) = m + 1/2.
Step 9: Calculate 1000/600, which simplifies to 5/3 or approximately 1.67.
Step 10: Set up the equation: 1.67 = m + 1/2.
Step 11: Solve for m: m = 1.67 - 0.5 = 1.17.
Step 12: Since m must be an integer, the closest integer values for m are 1 or 2, which can be tested for destructive interference.
