A ray of light in a medium with n=1.33 strikes the boundary with air at an angle

A ray of light in a medium with n=1.33 strikes the boundary with air at an angle of 45°. What is the behavior of the ray?

A ray of light in a medium with n=1.33 strikes the boundary with air at an angle of 45°. What is the behavior of the ray?

Step 1: Identify the medium where the ray of light is currently traveling. In this case, it is a medium with a refractive index (n) of 1.33.
Step 2: Determine the angle at which the ray of light strikes the boundary with air. The angle given is 45°.
Step 3: Calculate the critical angle (θc) for the boundary between the medium and air. The critical angle can be found using the formula: θc = arcsin(n2/n1), where n1 is the refractive index of the medium (1.33) and n2 is the refractive index of air (approximately 1.00).
Step 4: Calculate θc: θc = arcsin(1.00/1.33) which is approximately 48.6°.
Step 5: Compare the angle of incidence (45°) with the critical angle (48.6°). Since 45° is less than 48.6°, the ray will not undergo total internal reflection.
Step 6: Conclude that the ray will partially reflect and partially refract at the boundary.

Refraction and Reflection – The behavior of light at the boundary between two media, including the critical angle and the conditions for partial reflection and refraction.
Critical Angle – The minimum angle of incidence at which total internal reflection occurs; if the angle of incidence is less than the critical angle, some light will refract and some will reflect.