If the wavelength of light used in a double-slit experiment is 600 nm and the di

What’s inside this PDF?

Question: If the wavelength of light used in a double-slit experiment is 600 nm and the distance between the slits is 0.3 mm, what is the distance between the first and second bright fringes on the screen placed 2 m away?

Options:

0.4 m
0.6 m
0.8 m
0.2 m

Correct Answer: 0.4 m

Solution:

Distance between fringes = (λD)/d = (600 x 10^-9 m * 2 m) / (0.3 x 10^-3 m) = 0.004 m = 0.4 m.

Practice Questions

Q1

If the wavelength of light used in a double-slit experiment is 600 nm and the distance between the slits is 0.3 mm, what is the distance between the first and second bright fringes on the screen placed 2 m away?

0.4 m
0.6 m
0.8 m
0.2 m

Questions & Step-by-Step Solutions

If the wavelength of light used in a double-slit experiment is 600 nm and the distance between the slits is 0.3 mm, what is the distance between the first and second bright fringes on the screen placed 2 m away?

Step 1: Identify the given values from the problem. The wavelength of light (λ) is 600 nm, the distance between the slits (d) is 0.3 mm, and the distance to the screen (D) is 2 m.
Step 2: Convert the units to meters for consistency. 600 nm is equal to 600 x 10^-9 m, and 0.3 mm is equal to 0.3 x 10^-3 m.
Step 3: Use the formula for the distance between fringes: Distance between fringes = (λD) / d.
Step 4: Substitute the values into the formula: Distance between fringes = (600 x 10^-9 m * 2 m) / (0.3 x 10^-3 m).
Step 5: Calculate the numerator: 600 x 10^-9 m * 2 m = 1200 x 10^-9 m = 1.2 x 10^-6 m.
Step 6: Calculate the denominator: 0.3 x 10^-3 m = 0.0003 m.
Step 7: Divide the numerator by the denominator: (1.2 x 10^-6 m) / (0.0003 m) = 0.004 m.
Step 8: Convert the result to a more understandable unit if needed: 0.004 m is equal to 0.4 cm.

Double-slit interference – The phenomenon where light waves passing through two closely spaced slits create an interference pattern of bright and dark fringes on a screen.
Wavelength and fringe spacing – The relationship between the wavelength of light, the distance between the slits, and the distance to the screen in determining the spacing of interference fringes.

If the wavelength of light used in a double-slit experiment is 600 nm and the di

What’s inside this PDF?

If the wavelength of light used in a double-slit experiment is 600 nm and the di

Practice Questions

Questions & Step-by-Step Solutions

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