What is the phase difference between two points on a wave that are 1/4 wavelengt

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Question: What is the phase difference between two points on a wave that are 1/4 wavelength apart?

Options:

Correct Answer: π/2 radians

Solution:

The phase difference Δφ between two points separated by a distance of λ/4 is given by Δφ = (2π/λ)(λ/4) = π/2 radians.

What is the phase difference between two points on a wave that are 1/4 wavelength apart?

What is the phase difference between two points on a wave that are 1/4 wavelength apart?

Step 1: Understand that a wave has a wavelength (λ), which is the distance between two consecutive points that are in phase.
Step 2: Recognize that if two points are 1/4 of a wavelength apart, this distance can be expressed as λ/4.
Step 3: The phase difference (Δφ) is calculated using the formula Δφ = (2π/λ) * distance.
Step 4: Substitute the distance (λ/4) into the formula: Δφ = (2π/λ) * (λ/4).
Step 5: Simplify the equation: Δφ = (2π/λ) * (λ/4) = (2π/4) = π/2 radians.
Step 6: Conclude that the phase difference between two points on a wave that are 1/4 wavelength apart is π/2 radians.

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