Question: In a double-slit experiment, if the distance between the slits is 0.5 mm and the distance to the screen is 2 m, what is the distance between the first and second bright fringes if the wavelength of light used is 500 nm?
Options:
Correct Answer: 1 cm
Solution:
Using the formula for fringe separation, y = (λD)/d, we find y = (500 x 10^-9 m * 2 m) / (0.5 x 10^-3 m) = 2 cm.