My Learning Cart
?
Categories
Account

What is the critical angle for total internal reflection from water (n = 1.33) t

₹0.0
Login to Download
  • 📥 Instant PDF Download
  • ♾ Lifetime Access
  • 🛡 Secure & Original Content

What’s inside this PDF?

Question: What is the critical angle for total internal reflection from water (n = 1.33) to air (n = 1)?

Options:

  1. 48.6 degrees
  2. 53.1 degrees
  3. 60 degrees
  4. 90 degrees

Correct Answer: 53.1 degrees

Solution: 

The critical angle (θc) can be calculated using sin(θc) = n2/n1. Thus, sin(θc) = 1/1.33, giving θc ≈ 53.1 degrees.

What is the critical angle for total internal reflection from water (n = 1.33) t

Practice Questions

Q1
What is the critical angle for total internal reflection from water (n = 1.33) to air (n = 1)?
  1. 48.6 degrees
  2. 53.1 degrees
  3. 60 degrees
  4. 90 degrees

Questions & Step-by-Step Solutions

What is the critical angle for total internal reflection from water (n = 1.33) to air (n = 1)?
  • Step 1: Identify the refractive indices. For water, n1 = 1.33 and for air, n2 = 1.
  • Step 2: Use the formula for critical angle: sin(θc) = n2/n1.
  • Step 3: Substitute the values into the formula: sin(θc) = 1/1.33.
  • Step 4: Calculate the value of sin(θc): sin(θc) ≈ 0.7519.
  • Step 5: Use the inverse sine function to find θc: θc = sin⁻¹(0.7519).
  • Step 6: Calculate θc, which is approximately 53.1 degrees.
No concepts available.
Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely
Home Practice Performance eBooks