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What is the critical angle for total internal reflection from water (n = 1.33) t
What is the critical angle for total internal reflection from water (n = 1.33) to air (n = 1)?
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Practice Questions
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Q1
What is the critical angle for total internal reflection from water (n = 1.33) to air (n = 1)?
48.6 degrees
53.1 degrees
60 degrees
90 degrees
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The critical angle (θc) can be calculated using sin(θc) = n2/n1. Thus, sin(θc) = 1/1.33, giving θc ≈ 53.1 degrees.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the critical angle for total internal reflection from water (n = 1.33) to air (n = 1)?
Solution:
The critical angle (θc) can be calculated using sin(θc) = n2/n1. Thus, sin(θc) = 1/1.33, giving θc ≈ 53.1 degrees.
Steps: 6
Show Steps
Step 1: Identify the refractive indices. For water, n1 = 1.33 and for air, n2 = 1.
Step 2: Use the formula for critical angle: sin(θc) = n2/n1.
Step 3: Substitute the values into the formula: sin(θc) = 1/1.33.
Step 4: Calculate the value of sin(θc): sin(θc) ≈ 0.7519.
Step 5: Use the inverse sine function to find θc: θc = sin⁻¹(0.7519).
Step 6: Calculate θc, which is approximately 53.1 degrees.
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