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What is the critical angle for total internal reflection from water (n = 1.33) t

Practice Questions

Q1
What is the critical angle for total internal reflection from water (n = 1.33) to air (n = 1)?
  1. 48.6 degrees
  2. 53.1 degrees
  3. 60 degrees
  4. 90 degrees

Questions & Step-by-Step Solutions

What is the critical angle for total internal reflection from water (n = 1.33) to air (n = 1)?
  • Step 1: Identify the refractive indices. For water, n1 = 1.33 and for air, n2 = 1.
  • Step 2: Use the formula for critical angle: sin(θc) = n2/n1.
  • Step 3: Substitute the values into the formula: sin(θc) = 1/1.33.
  • Step 4: Calculate the value of sin(θc): sin(θc) ≈ 0.7519.
  • Step 5: Use the inverse sine function to find θc: θc = sin⁻¹(0.7519).
  • Step 6: Calculate θc, which is approximately 53.1 degrees.
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