In a toroidal solenoid with N turns and carrying current I, what is the magnetic

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Question: In a toroidal solenoid with N turns and carrying current I, what is the magnetic field inside the toroid?

Options:

Correct Answer: μ₀NI/r

Solution:

Using Ampere\'s Law, B = μ₀NI/2πr inside a toroidal solenoid.

In a toroidal solenoid with N turns and carrying current I, what is the magnetic field inside the toroid?

In a toroidal solenoid with N turns and carrying current I, what is the magnetic field inside the toroid?

Step 1: Understand what a toroidal solenoid is. It is a coil of wire shaped like a donut (torus) that carries an electric current.
Step 2: Identify the key variables: N is the number of turns of the wire, I is the current flowing through the wire, and r is the distance from the center of the toroid to the point where you want to find the magnetic field.
Step 3: Recall Ampere's Law, which relates the magnetic field around a closed loop to the current passing through that loop.
Step 4: Apply Ampere's Law to the toroidal solenoid. The formula for the magnetic field (B) inside the toroid is given by B = μ₀NI/2πr.
Step 5: Understand that μ₀ is the permeability of free space, a constant that helps determine the strength of the magnetic field.

Ampere's Law – Ampere's Law relates the magnetic field around a closed loop to the electric current passing through the loop.
Toroidal Solenoid – A toroidal solenoid is a coil of wire shaped like a doughnut, where the magnetic field is confined within the core of the toroid.
Magnetic Field Calculation – The formula for the magnetic field inside a toroidal solenoid is derived from Ampere's Law, taking into account the number of turns and the radius.