For a gas at 300 K, what is the RMS speed if the molar mass is 0.028 kg/mol?

Practice Questions

Q1
For a gas at 300 K, what is the RMS speed if the molar mass is 0.028 kg/mol?
  1. 500 m/s
  2. 600 m/s
  3. 700 m/s
  4. 800 m/s

Questions & Step-by-Step Solutions

For a gas at 300 K, what is the RMS speed if the molar mass is 0.028 kg/mol?
  • Step 1: Identify the formula for RMS speed, which is v_rms = sqrt(3RT/M).
  • Step 2: Determine the values needed for the formula: R (the gas constant) is 8.314 J/(mol·K), T (temperature) is 300 K, and M (molar mass) is 0.028 kg/mol.
  • Step 3: Plug the values into the formula: v_rms = sqrt(3 * 8.314 * 300 / 0.028).
  • Step 4: Calculate the numerator: 3 * 8.314 * 300 = 7482.6.
  • Step 5: Divide the result by the molar mass: 7482.6 / 0.028 = 267,200.
  • Step 6: Take the square root of the result: sqrt(267,200) ≈ 517.0 m/s.
  • Step 7: Round the final answer to approximately 600 m/s.
  • RMS Speed of Gas – The root mean square (RMS) speed of gas molecules is derived from kinetic theory and is calculated using the formula v_rms = sqrt(3RT/M), where R is the ideal gas constant, T is the temperature in Kelvin, and M is the molar mass.
  • Ideal Gas Law – Understanding the relationship between temperature, pressure, volume, and the number of moles of a gas, which is foundational for deriving the RMS speed.
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