A force of 10 N is applied to a 2 kg object at rest. What is the final velocity

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Question: A force of 10 N is applied to a 2 kg object at rest. What is the final velocity of the object after 5 seconds?

Options:

Correct Answer: 5 m/s

Solution:

Using F = ma, a = F/m = 10 N / 2 kg = 5 m/s². Final velocity v = u + at = 0 + 5 * 5 = 25 m/s.

A force of 10 N is applied to a 2 kg object at rest. What is the final velocity of the object after 5 seconds?

A force of 10 N is applied to a 2 kg object at rest. What is the final velocity of the object after 5 seconds?

Step 1: Identify the given values. We have a force (F) of 10 N and a mass (m) of 2 kg.
Step 2: Use the formula F = ma to find the acceleration (a). Rearranging gives us a = F/m.
Step 3: Substitute the values into the formula: a = 10 N / 2 kg.
Step 4: Calculate the acceleration: a = 5 m/s².
Step 5: Identify the initial velocity (u) of the object. Since it is at rest, u = 0 m/s.
Step 6: Use the formula for final velocity (v): v = u + at.
Step 7: Substitute the values into the formula: v = 0 + (5 m/s² * 5 s).
Step 8: Calculate the final velocity: v = 25 m/s.

Newton's Second Law of Motion – This law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
Kinematic Equations – These equations relate the variables of motion (initial velocity, final velocity, acceleration, time, and displacement) for uniformly accelerated motion.