A car accelerates from rest to a speed of 30 m/s in 10 seconds. What is the dist

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Question: A car accelerates from rest to a speed of 30 m/s in 10 seconds. What is the distance covered by the car during this time?

Options:

Correct Answer: 300 m

Solution:

Using the formula d = ut + 0.5at², where u = 0, a = (30 m/s) / 10 s = 3 m/s², we get d = 0 + 0.5 * 3 * (10)² = 150 m.

A car accelerates from rest to a speed of 30 m/s in 10 seconds. What is the distance covered by the car during this time?

A car accelerates from rest to a speed of 30 m/s in 10 seconds. What is the distance covered by the car during this time?

Step 1: Identify the initial speed (u) of the car. Since the car starts from rest, u = 0 m/s.
Step 2: Identify the final speed (v) of the car. The car accelerates to a speed of 30 m/s.
Step 3: Identify the time (t) taken to reach this speed. The time is given as 10 seconds.
Step 4: Calculate the acceleration (a) of the car using the formula a = (v - u) / t. Here, a = (30 m/s - 0 m/s) / 10 s = 3 m/s².
Step 5: Use the formula for distance (d) covered during acceleration: d = ut + 0.5at².
Step 6: Substitute the values into the formula: d = 0 + 0.5 * 3 m/s² * (10 s)².
Step 7: Calculate (10 s)², which is 100 s².
Step 8: Now calculate d = 0 + 0.5 * 3 * 100 = 0 + 150 = 150 m.
Step 9: Conclude that the distance covered by the car during this time is 150 meters.

Kinematics – The study of motion, specifically how objects move under the influence of forces, including concepts of acceleration, velocity, and distance.
Equations of Motion – The use of kinematic equations to relate distance, initial velocity, acceleration, and time.