Question: If the RMS speed of a gas is 400 m/s and its molar mass is 16 g/mol, what is the temperature of the gas?
Options:
Correct Answer: 400 K
Solution:
Using the formula v_rms = sqrt((3RT)/M), we can rearrange to find T: T = (M * v_rms^2) / (3R). Substituting M = 0.016 kg/mol and v_rms = 400 m/s gives T = 400 K.