A cyclist is moving at 15 m/s and a pedestrian at 5 m/s in the same direction. H

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What’s inside this PDF?

Question: A cyclist is moving at 15 m/s and a pedestrian at 5 m/s in the same direction. How fast does the cyclist appear to be moving to the pedestrian?

Options:

10 m/s
15 m/s
20 m/s
5 m/s

Correct Answer: 10 m/s

Solution:

Relative speed = Speed of cyclist - Speed of pedestrian = 15 m/s - 5 m/s = 10 m/s.

A cyclist is moving at 15 m/s and a pedestrian at 5 m/s in the same direction. H

Practice Questions

A cyclist is moving at 15 m/s and a pedestrian at 5 m/s in the same direction. How fast does the cyclist appear to be moving to the pedestrian?

10 m/s
15 m/s
20 m/s
5 m/s

Questions & Step-by-Step Solutions

A cyclist is moving at 15 m/s and a pedestrian at 5 m/s in the same direction. How fast does the cyclist appear to be moving to the pedestrian?

Step 1: Identify the speed of the cyclist, which is 15 m/s.
Step 2: Identify the speed of the pedestrian, which is 5 m/s.
Step 3: Since both are moving in the same direction, we need to find the difference in their speeds.
Step 4: Subtract the speed of the pedestrian from the speed of the cyclist: 15 m/s - 5 m/s.
Step 5: Calculate the result of the subtraction, which is 10 m/s.
Step 6: Conclude that the cyclist appears to be moving at 10 m/s relative to the pedestrian.

Relative Speed – The speed of one object as observed from another object moving in the same direction.

A cyclist is moving at 15 m/s and a pedestrian at 5 m/s in the same direction. H

What’s inside this PDF?

A cyclist is moving at 15 m/s and a pedestrian at 5 m/s in the same direction. H

Practice Questions

Questions & Step-by-Step Solutions

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