What is the gravitational field strength at the surface of a planet with mass 6
Practice Questions
Q1
What is the gravitational field strength at the surface of a planet with mass 6 x 10^24 kg and radius 6.4 x 10^6 m?
9.8 N/kg
6.67 N/kg
3.2 N/kg
12.5 N/kg
Questions & Step-by-Step Solutions
What is the gravitational field strength at the surface of a planet with mass 6 x 10^24 kg and radius 6.4 x 10^6 m?
Step 1: Identify the formula for gravitational field strength, which is g = GM/R².
Step 2: Identify the values needed for the formula: G (gravitational constant) = 6.67 x 10^-11 N(m/kg)², M (mass of the planet) = 6 x 10^24 kg, and R (radius of the planet) = 6.4 x 10^6 m.
Step 3: Substitute the values into the formula: g = (6.67 x 10^-11 * 6 x 10^24) / (6.4 x 10^6)².
Step 4: Calculate the denominator (6.4 x 10^6)² to get 4.096 x 10^13 m².
Step 5: Calculate the numerator (6.67 x 10^-11 * 6 x 10^24) to get 4.002 x 10^14 N(m/kg)².
Step 6: Divide the numerator by the denominator: g = 4.002 x 10^14 / 4.096 x 10^13.
Step 7: Perform the division to find g, which equals approximately 9.8 N/kg.
