A projectile is launched at an angle of 30 degrees with an initial speed of 20 m/s. What is the maximum height reached by the projectile?
Practice Questions
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Q1
A projectile is launched at an angle of 30 degrees with an initial speed of 20 m/s. What is the maximum height reached by the projectile?
5 m
10 m
15 m
20 m
Using the formula: h = (u² * sin²θ) / (2g), where u = 20 m/s, θ = 30°, g = 9.8 m/s². h = (20² * (1/4)) / (2 * 9.8) = 5.1 m, approximately 5 m.
Questions & Step-by-step Solutions
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Q: A projectile is launched at an angle of 30 degrees with an initial speed of 20 m/s. What is the maximum height reached by the projectile?
Solution: Using the formula: h = (u² * sin²θ) / (2g), where u = 20 m/s, θ = 30°, g = 9.8 m/s². h = (20² * (1/4)) / (2 * 9.8) = 5.1 m, approximately 5 m.
