An object is thrown vertically upward with a speed of 30 m/s. How high will it r

An object is thrown vertically upward with a speed of 30 m/s. How high will it rise before coming to a momentary stop?

An object is thrown vertically upward with a speed of 30 m/s. How high will it rise before coming to a momentary stop?

Step 1: Identify the initial speed (u) of the object. In this case, u = 30 m/s.
Step 2: Recognize that at the highest point, the final speed (v) will be 0 m/s.
Step 3: Understand that the acceleration due to gravity (g) is approximately 9.8 m/s². Since the object is moving upward, we will use -g in our calculations.
Step 4: Use the formula for height (h) which is h = (v² - u²) / (2g).
Step 5: Substitute the values into the formula: h = (0 - 30²) / (2 * -9.8).
Step 6: Calculate 30², which is 900. So now we have h = (-900) / (-19.6).
Step 7: Divide -900 by -19.6 to find h. This gives h = 45.92 m.
Step 8: Round the answer to the nearest whole number, which is approximately 45 m.

Kinematics – The question tests the understanding of kinematic equations related to motion under constant acceleration, specifically vertical motion under gravity.
Energy Conservation – It also touches on the concept of energy conservation, where kinetic energy is converted to potential energy at the highest point.