What is the potential difference between two points in an electric field if the

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Question: What is the potential difference between two points in an electric field if the work done in moving a charge of +2μC is 0.04 J?

Options:

Correct Answer: 20 V

Solution:

Potential difference V = W/q = 0.04 J / (2 × 10^-6 C) = 20 V.

What is the potential difference between two points in an electric field if the work done in moving a charge of +2μC is 0.04 J?

What is the potential difference between two points in an electric field if the work done in moving a charge of +2μC is 0.04 J?

Step 1: Identify the formula for potential difference (V), which is V = W/q, where W is the work done and q is the charge.
Step 2: Note the values given in the question: Work done (W) is 0.04 J and the charge (q) is +2μC.
Step 3: Convert the charge from microcoulombs (μC) to coulombs (C). Since 1μC = 10^-6 C, +2μC = 2 × 10^-6 C.
Step 4: Substitute the values into the formula: V = 0.04 J / (2 × 10^-6 C).
Step 5: Calculate the potential difference: V = 0.04 J / 0.000002 C = 20 V.

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