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A charge of +2μC is placed in an electric field of 1000 N/C. What is the force e
A charge of +2μC is placed in an electric field of 1000 N/C. What is the force experienced by the charge? (2000)
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A charge of +2μC is placed in an electric field of 1000 N/C. What is the force experienced by the charge? (2000)
2000 N
2 N
0.002 N
1000 N
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The force F on a charge in an electric field is given by F = qE. Here, F = 2 * 10^-6 C * 1000 N/C = 0.002 N.
Questions & Step-by-step Solutions
1 item
Q
Q: A charge of +2μC is placed in an electric field of 1000 N/C. What is the force experienced by the charge? (2000)
Solution:
The force F on a charge in an electric field is given by F = qE. Here, F = 2 * 10^-6 C * 1000 N/C = 0.002 N.
Steps: 5
Show Steps
Step 1: Identify the charge (q) and the electric field (E). Here, q = +2μC (microcoulombs) and E = 1000 N/C (newtons per coulomb).
Step 2: Convert the charge from microcoulombs to coulombs. 2μC = 2 * 10^-6 C.
Step 3: Use the formula for force (F) in an electric field, which is F = qE.
Step 4: Substitute the values into the formula: F = (2 * 10^-6 C) * (1000 N/C).
Step 5: Calculate the force: F = 2 * 10^-6 * 1000 = 0.002 N.
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