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If the resistance P in a Wheatstone bridge is 10 ohms, Q is 15 ohms, R is 5 ohms

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Question: If the resistance P in a Wheatstone bridge is 10 ohms, Q is 15 ohms, R is 5 ohms, and S is 7.5 ohms, what is the condition for the bridge to be balanced?

Options:

  1. P/Q = R/S
  2. P/R = Q/S
  3. P/S = Q/R
  4. P + Q = R + S

Correct Answer: P/Q = R/S

Solution: 

The condition for balance is P/Q = R/S, which is not satisfied here.

If the resistance P in a Wheatstone bridge is 10 ohms, Q is 15 ohms, R is 5 ohms

Practice Questions

Q1
If the resistance P in a Wheatstone bridge is 10 ohms, Q is 15 ohms, R is 5 ohms, and S is 7.5 ohms, what is the condition for the bridge to be balanced?
  1. P/Q = R/S
  2. P/R = Q/S
  3. P/S = Q/R
  4. P + Q = R + S

Questions & Step-by-Step Solutions

If the resistance P in a Wheatstone bridge is 10 ohms, Q is 15 ohms, R is 5 ohms, and S is 7.5 ohms, what is the condition for the bridge to be balanced?
  • Step 1: Understand that a Wheatstone bridge has four resistances: P, Q, R, and S.
  • Step 2: Identify the values of the resistances: P = 10 ohms, Q = 15 ohms, R = 5 ohms, S = 7.5 ohms.
  • Step 3: Write down the condition for the bridge to be balanced, which is P/Q = R/S.
  • Step 4: Substitute the values into the equation: 10/15 and 5/7.5.
  • Step 5: Calculate 10/15, which simplifies to 2/3.
  • Step 6: Calculate 5/7.5, which simplifies to 2/3 as well.
  • Step 7: Compare the two results: since 2/3 = 2/3, the condition for balance is satisfied.
  • Wheatstone Bridge – A circuit used to measure unknown resistances by balancing two legs of a bridge circuit.
  • Balance Condition – The condition for a Wheatstone bridge to be balanced is given by the ratio of the resistances: P/Q = R/S.
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