If the resistance P in a Wheatstone bridge is 10 ohms, Q is 15 ohms, R is 5 ohms, and S is 7.5 ohms, what is the condition for the bridge to be balanced?
Practice Questions
1 question
Q1
If the resistance P in a Wheatstone bridge is 10 ohms, Q is 15 ohms, R is 5 ohms, and S is 7.5 ohms, what is the condition for the bridge to be balanced?
P/Q = R/S
P/R = Q/S
P/S = Q/R
P + Q = R + S
The condition for balance is P/Q = R/S, which is not satisfied here.
Questions & Step-by-step Solutions
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Q
Q: If the resistance P in a Wheatstone bridge is 10 ohms, Q is 15 ohms, R is 5 ohms, and S is 7.5 ohms, what is the condition for the bridge to be balanced?
Solution: The condition for balance is P/Q = R/S, which is not satisfied here.
Steps: 7
Step 1: Understand that a Wheatstone bridge has four resistances: P, Q, R, and S.
Step 2: Identify the values of the resistances: P = 10 ohms, Q = 15 ohms, R = 5 ohms, S = 7.5 ohms.
Step 3: Write down the condition for the bridge to be balanced, which is P/Q = R/S.
Step 4: Substitute the values into the equation: 10/15 and 5/7.5.
Step 5: Calculate 10/15, which simplifies to 2/3.
Step 6: Calculate 5/7.5, which simplifies to 2/3 as well.
Step 7: Compare the two results: since 2/3 = 2/3, the condition for balance is satisfied.
