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In a Wheatstone bridge, if R1 = 4Ω, R2 = 6Ω, and R3 = 12Ω, what is the value of
In a Wheatstone bridge, if R1 = 4Ω, R2 = 6Ω, and R3 = 12Ω, what is the value of R4 for the bridge to be balanced?
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Q1
In a Wheatstone bridge, if R1 = 4Ω, R2 = 6Ω, and R3 = 12Ω, what is the value of R4 for the bridge to be balanced?
8Ω
9Ω
10Ω
12Ω
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Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (6 * 12) / 4 = 18Ω.
Questions & Step-by-step Solutions
1 item
Q
Q: In a Wheatstone bridge, if R1 = 4Ω, R2 = 6Ω, and R3 = 12Ω, what is the value of R4 for the bridge to be balanced?
Solution:
Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (6 * 12) / 4 = 18Ω.
Steps: 7
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Step 1: Write down the values of the resistors: R1 = 4Ω, R2 = 6Ω, R3 = 12Ω.
Step 2: Recall the balance condition for a Wheatstone bridge, which is R1/R2 = R3/R4.
Step 3: Rearrange the balance condition to solve for R4: R4 = (R2 * R3) / R1.
Step 4: Substitute the values into the equation: R4 = (6 * 12) / 4.
Step 5: Calculate the multiplication: 6 * 12 = 72.
Step 6: Divide the result by R1: 72 / 4 = 18.
Step 7: Conclude that the value of R4 for the bridge to be balanced is 18Ω.
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