In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 5Ω, and R3 = 15Ω, what is the

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Question: In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 5Ω, and R3 = 15Ω, what is the value of R4?

Options:

Correct Answer: 12.5Ω

Solution:

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (5 * 15) / 10 = 7.5Ω.

In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 5Ω, and R3 = 15Ω, what is the value of R4?

In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 5Ω, and R3 = 15Ω, what is the value of R4?

Step 1: Understand that in a balanced Wheatstone bridge, the ratio of the resistances is equal. This means R1/R2 = R3/R4.
Step 2: Identify the values given in the question: R1 = 10Ω, R2 = 5Ω, R3 = 15Ω.
Step 3: Write down the balance condition: R1/R2 = R3/R4.
Step 4: Substitute the known values into the equation: 10Ω / 5Ω = 15Ω / R4.
Step 5: Simplify the left side of the equation: 2 = 15Ω / R4.
Step 6: Rearrange the equation to solve for R4: R4 = 15Ω / 2.
Step 7: Calculate the value of R4: R4 = 7.5Ω.

Wheatstone Bridge Balance Condition – The Wheatstone bridge is a circuit used to measure unknown resistances by balancing two legs of a bridge circuit. The balance condition states that the ratio of the resistances in one leg is equal to the ratio in the other leg.