In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 5Ω, and R3 = 15Ω, what is the

In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 5Ω, and R3 = 15Ω, what is the value of R4?

In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 5Ω, and R3 = 15Ω, what is the value of R4?

Step 1: Understand that in a balanced Wheatstone bridge, the ratio of the resistances is equal. This means R1/R2 = R3/R4.
Step 2: Identify the values given in the question: R1 = 10Ω, R2 = 5Ω, R3 = 15Ω.
Step 3: Write down the balance condition: R1/R2 = R3/R4.
Step 4: Substitute the known values into the equation: 10Ω / 5Ω = 15Ω / R4.
Step 5: Simplify the left side of the equation: 2 = 15Ω / R4.
Step 6: Rearrange the equation to solve for R4: R4 = 15Ω / 2.
Step 7: Calculate the value of R4: R4 = 7.5Ω.

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