What is the total current in a circuit with a 9V battery and two 3Ω resistors in

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Question: What is the total current in a circuit with a 9V battery and two 3Ω resistors in parallel?

Options:

Correct Answer: 2A

Solution:

Total resistance R = 1/(1/3 + 1/3) = 1.5Ω; I = V/R = 9V/1.5Ω = 6A.

What is the total current in a circuit with a 9V battery and two 3Ω resistors in parallel?

What is the total current in a circuit with a 9V battery and two 3Ω resistors in parallel?

Step 1: Identify the voltage of the battery, which is 9V.
Step 2: Identify the resistance of each resistor, which is 3Ω.
Step 3: Since the resistors are in parallel, use the formula for total resistance: R_total = 1 / (1/R1 + 1/R2).
Step 4: Substitute the values: R_total = 1 / (1/3 + 1/3).
Step 5: Calculate the sum inside the parentheses: 1/3 + 1/3 = 2/3.
Step 6: Now calculate R_total: R_total = 1 / (2/3) = 3/2 = 1.5Ω.
Step 7: Use Ohm's Law to find the total current: I = V / R_total.
Step 8: Substitute the values: I = 9V / 1.5Ω.
Step 9: Calculate the current: I = 6A.

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