In a circuit with a 24V battery and two resistors of 8Ω and 16Ω in series, what

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Question: In a circuit with a 24V battery and two resistors of 8Ω and 16Ω in series, what is the voltage across the 16Ω resistor?

Options:

Correct Answer: 12V

Solution:

Voltage across R2 = (R2/(R1+R2)) * V = (16/(8+16)) * 24 = 16V.

In a circuit with a 24V battery and two resistors of 8Ω and 16Ω in series, what is the voltage across the 16Ω resistor?

In a circuit with a 24V battery and two resistors of 8Ω and 16Ω in series, what is the voltage across the 16Ω resistor?

Step 1: Identify the total voltage in the circuit, which is given as 24V from the battery.
Step 2: Identify the resistors in the circuit. We have R1 = 8Ω and R2 = 16Ω.
Step 3: Calculate the total resistance in the circuit by adding the two resistors together: Total Resistance = R1 + R2 = 8Ω + 16Ω = 24Ω.
Step 4: Use the formula to find the voltage across the 16Ω resistor (R2). The formula is: Voltage across R2 = (R2 / Total Resistance) * Total Voltage.
Step 5: Substitute the values into the formula: Voltage across R2 = (16Ω / 24Ω) * 24V.
Step 6: Simplify the calculation: Voltage across R2 = (16 / 24) * 24 = 16V.

Voltage Division – The principle that the voltage across a resistor in a series circuit is proportional to its resistance relative to the total resistance.