In a circuit with a 9V battery and two resistors of 3 ohms and 6 ohms in series,
Practice Questions
Q1
In a circuit with a 9V battery and two resistors of 3 ohms and 6 ohms in series, what is the voltage drop across the 6 ohm resistor?
6V
3V
9V
4.5V
Questions & Step-by-Step Solutions
In a circuit with a 9V battery and two resistors of 3 ohms and 6 ohms in series, what is the voltage drop across the 6 ohm resistor?
Step 1: Identify the total resistance in the circuit. Add the resistances of the two resistors: 3 ohms + 6 ohms = 9 ohms.
Step 2: Use Ohm's Law to find the current in the circuit. Ohm's Law states that I = V / R. Here, V is the voltage of the battery (9V) and R is the total resistance (9 ohms). So, I = 9V / 9 ohms = 1 A.
Step 3: Calculate the voltage drop across the 6 ohm resistor using Ohm's Law again. The formula is V = I * R. Here, I is the current (1 A) and R is the resistance of the 6 ohm resistor. So, V = 1 A * 6 ohms = 6V.
