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What is the magnitude of the vector C = (6, 8, 10)?
What is the magnitude of the vector C = (6, 8, 10)?
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Q1
What is the magnitude of the vector C = (6, 8, 10)?
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Magnitude |C| = √(6^2 + 8^2 + 10^2) = √(36 + 64 + 100) = √200 = 10√2.
Questions & Step-by-step Solutions
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Q
Q: What is the magnitude of the vector C = (6, 8, 10)?
Solution:
Magnitude |C| = √(6^2 + 8^2 + 10^2) = √(36 + 64 + 100) = √200 = 10√2.
Steps: 7
Show Steps
Step 1: Identify the components of the vector C. The vector C has three components: 6, 8, and 10.
Step 2: Square each component of the vector. Calculate 6^2, 8^2, and 10^2.
Step 3: Calculate 6^2 = 36, 8^2 = 64, and 10^2 = 100.
Step 4: Add the squared values together. Calculate 36 + 64 + 100.
Step 5: The sum is 200.
Step 6: Take the square root of the sum. Calculate √200.
Step 7: Simplify √200. It can be written as √(100 * 2) = √100 * √2 = 10√2.
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