If a person is standing 50 meters away from a building and the angle of elevatio
Practice Questions
Q1
If a person is standing 50 meters away from a building and the angle of elevation to the top of the building is 60 degrees, what is the height of the building?
25√3 meters
50√3 meters
75 meters
100 meters
Questions & Step-by-Step Solutions
If a person is standing 50 meters away from a building and the angle of elevation to the top of the building is 60 degrees, what is the height of the building?
Step 1: Understand the problem. You have a person standing 50 meters away from a building and looking up at the top of the building at an angle of 60 degrees.
Step 2: Visualize the situation. Imagine a right triangle where one side is the height of the building, the other side is the distance from the person to the building (50 meters), and the angle between the ground and the line of sight to the top of the building is 60 degrees.
Step 3: Use the tangent function. In a right triangle, the tangent of an angle is equal to the opposite side (height of the building) divided by the adjacent side (distance from the person to the building). So, tan(60 degrees) = height / 50 meters.
Step 4: Find the value of tan(60 degrees). The value of tan(60 degrees) is √3.
Step 5: Set up the equation. You can write the equation as height = 50 * tan(60 degrees).
Step 6: Substitute the value of tan(60 degrees) into the equation. This gives you height = 50 * √3.
Step 7: Calculate the height. The height of the building is 50√3 meters.
