If \( y = \tan^{-1}(x) + \tan^{-1}(y) \), what is the value of \( y \) when \( x
Practice Questions
Q1
If \( y = \tan^{-1}(x) + \tan^{-1}(y) \), what is the value of \( y \) when \( x = 1 \)?
0
1
\( \frac{\pi}{4} \)
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Questions & Step-by-Step Solutions
If \( y = \tan^{-1}(x) + \tan^{-1}(y) \), what is the value of \( y \) when \( x = 1 \)?
Step 1: Start with the equation given in the question: y = tan^(-1)(x) + tan^(-1)(y).
Step 2: Substitute x = 1 into the equation: y = tan^(-1)(1) + tan^(-1)(y).
Step 3: Calculate tan^(-1)(1). The value of tan^(-1)(1) is π/4 because the tangent of π/4 is 1.
Step 4: Now the equation becomes: y = π/4 + tan^(-1)(y).
Step 5: To solve for y, we can use the fact that tan^(-1)(y) is the angle whose tangent is y. This means we can express y in terms of tangent: y = π/4 + tan^(-1)(y).
Step 6: We can assume y = k, where k is some value we want to find. So we rewrite the equation: k = π/4 + tan^(-1)(k).
Step 7: We can find the value of k by recognizing that if k = π/4, then tan^(-1)(k) = tan^(-1)(π/4) = π/4.
Step 8: Substitute k = π/4 back into the equation: π/4 = π/4 + tan^(-1)(π/4).
Step 9: Since both sides are equal, we conclude that y = π/4 is a valid solution.
