Question: If \\( y = \\cot^{-1}(x) \\), what is \\( \\frac{dy}{dx} \\)?
Options:
\\( -\\frac{1}{1+x^2} \\)
\\( \\frac{1}{1+x^2} \\)
0
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Correct Answer: \\( -\\frac{1}{1+x^2} \\)
Solution:
The derivative of \\( y = \\cot^{-1}(x) \\) is \\( -\\frac{1}{1+x^2} \\).
If \( y = \cot^{-1}(x) \), what is \( \frac{dy}{dx} \)?
Practice Questions
Q1
If \( y = \cot^{-1}(x) \), what is \( \frac{dy}{dx} \)?
\( -\frac{1}{1+x^2} \)
\( \frac{1}{1+x^2} \)
0
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Questions & Step-by-Step Solutions
If \( y = \cot^{-1}(x) \), what is \( \frac{dy}{dx} \)?
Inverse Trigonometric Functions – Understanding the derivatives of inverse trigonometric functions, specifically the derivative of cotangent inverse.
Chain Rule – Applying the chain rule in differentiation when dealing with inverse functions.
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