If the vertex of the parabola y = ax^2 + bx + c is at (1, -2), what is the value

Practice Questions

Q1
If the vertex of the parabola y = ax^2 + bx + c is at (1, -2), what is the value of a if b = 4 and c = -6?
  1. 1
  2. 2
  3. 3
  4. 4

Questions & Step-by-Step Solutions

If the vertex of the parabola y = ax^2 + bx + c is at (1, -2), what is the value of a if b = 4 and c = -6?
  • Step 1: Identify the formula for the x-coordinate of the vertex of a parabola, which is x = -b/(2a).
  • Step 2: Substitute the given value of b (which is 4) into the formula: x = -4/(2a).
  • Step 3: Set the x-coordinate of the vertex (which is 1) equal to the expression from Step 2: 1 = -4/(2a).
  • Step 4: To eliminate the fraction, multiply both sides of the equation by 2a: 2a * 1 = -4.
  • Step 5: This simplifies to 2a = -4.
  • Step 6: Now, solve for a by dividing both sides by 2: a = -4 / 2.
  • Step 7: Calculate the value: a = -2.
  • Vertex of a Parabola – Understanding how to find the vertex of a parabola using the formula x = -b/(2a) and its relation to the coefficients a, b, and c.
  • Quadratic Functions – Knowledge of the standard form of a quadratic function and how to manipulate it to find specific values.
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