Question: The function f(x) = { x^2, x < 0; 1, x = 0; x + 1, x > 0 } is continuous at x = 0?
Options:
Yes
No
Only from the right
Only from the left
Correct Answer: Yes
Solution:
Limit as x approaches 0 from left is 0, and f(0) = 1, hence it is not continuous at x = 0.
The function f(x) = { x^2, x < 0; 1, x = 0; x + 1, x > 0 } is continuous a
Practice Questions
Q1
The function f(x) = { x^2, x < 0; 1, x = 0; x + 1, x > 0 } is continuous at x = 0?
Yes
No
Only from the right
Only from the left
Questions & Step-by-Step Solutions
The function f(x) = { x^2, x < 0; 1, x = 0; x + 1, x > 0 } is continuous at x = 0?
Step 1: Identify the function f(x) which is defined in three parts: f(x) = x^2 when x < 0, f(x) = 1 when x = 0, and f(x) = x + 1 when x > 0.
Step 2: Find the limit of f(x) as x approaches 0 from the left (x < 0). This means we use the part of the function for x < 0, which is f(x) = x^2.
Step 3: Calculate the limit as x approaches 0 from the left: limit as x -> 0- of f(x) = limit as x -> 0- of x^2 = 0.
Step 4: Find the value of the function at x = 0. According to the function definition, f(0) = 1.
Step 5: Compare the limit from the left (which is 0) with the value of the function at x = 0 (which is 1). Since 0 is not equal to 1, the function is not continuous at x = 0.
Piecewise Functions β Understanding how piecewise functions are defined and how to evaluate them at specific points.
Continuity β The definition of continuity at a point, which requires that the limit from both sides equals the function value at that point.
Limits β Calculating limits from the left and right to determine the behavior of a function as it approaches a specific point.
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