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Evaluate the expression: tan^(-1)(1) + tan^(-1)(1) + tan^(-1)(0).

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Question: Evaluate the expression: tan^(-1)(1) + tan^(-1)(1) + tan^(-1)(0).

Options:

  1. π/2
  2. π
  3. 0
  4. π/4

Correct Answer: π/2

Solution:

tan^(-1)(1) = π/4, so the expression becomes π/4 + π/4 + 0 = π/2.

Evaluate the expression: tan^(-1)(1) + tan^(-1)(1) + tan^(-1)(0).

Practice Questions

Q1
Evaluate the expression: tan^(-1)(1) + tan^(-1)(1) + tan^(-1)(0).
  1. π/2
  2. π
  3. 0
  4. π/4

Questions & Step-by-Step Solutions

Evaluate the expression: tan^(-1)(1) + tan^(-1)(1) + tan^(-1)(0).
  • Step 1: Understand the notation tan^(-1)(x). This represents the inverse tangent function, also known as arctan. It gives the angle whose tangent is x.
  • Step 2: Calculate tan^(-1)(1). The angle whose tangent is 1 is Ï€/4 (or 45 degrees).
  • Step 3: Calculate tan^(-1)(0). The angle whose tangent is 0 is 0 (or 0 degrees).
  • Step 4: Substitute the values into the expression: tan^(-1)(1) + tan^(-1)(1) + tan^(-1)(0) becomes Ï€/4 + Ï€/4 + 0.
  • Step 5: Add the values together: Ï€/4 + Ï€/4 = 2(Ï€/4) = Ï€/2.
  • Step 6: The final result of the expression is Ï€/2.
  • Inverse Trigonometric Functions – Understanding the values of inverse tangent functions, particularly tan^(-1)(1) and tan^(-1)(0).
  • Addition of Angles – Applying the properties of addition for angles in trigonometric functions.
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